11331132000217 has 2 divisors, whose sum is σ = 11331132000218. Its totient is φ = 11331132000216.

The previous prime is 11331132000103. The next prime is 11331132000247. The reversal of 11331132000217 is 71200023113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11329713649296 + 1418350921 = 3365964^2 + 37661^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331132000217 - 2⁴³ = 2535038978009 is a prime.

It is a super-2 number, since 2×11331132000217² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331132000191 and 11331132000200.

It is not a weakly prime, because it can be changed into another prime (11331132000247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000108 + 5665566000109.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566000109).

Almost surely, 2^{11331132000217} is an apocalyptic number.

It is an amenable number.

11331132000217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132000217 is an equidigital number, since it uses as much as digits as its factorization.

11331132000217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 11331132000217 its reverse (71200023113311), we get a palindrome (82531155113528).

The spelling of 11331132000217 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, two hundred seventeen", and thus it is an aban number.