11331132000247 has 2 divisors, whose sum is σ = 11331132000248. Its totient is φ = 11331132000246.

The previous prime is 11331132000217. The next prime is 11331132000281. The reversal of 11331132000247 is 74200023113311.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331132000247 is a prime.

It is a super-2 number, since 2×11331132000247² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331132000217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000123 + 5665566000124.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566000124).

Almost surely, 2^{11331132000247} is an apocalyptic number.

11331132000247 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132000247 is an equidigital number, since it uses as much as digits as its factorization.

11331132000247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 28.

Adding to 11331132000247 its reverse (74200023113311), we get a palindrome (85531155113558).

The spelling of 11331132000247 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, two hundred forty-seven", and thus it is an aban number.