Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110010000100101101111 |
3 | 1111010020122001221012100122 |
4 | 2210320330012100211233 |
5 | 2441122124243004443 |
6 | 40033241123315155 |
7 | 2246435004561131 |
oct | 244707406204557 |
9 | 44106561835318 |
10 | 11331132000623 |
11 | 3679562681046 |
12 | 133007121babb |
13 | 6426a0cc11b6 |
14 | 2b26031d1051 |
15 | 149b37049968 |
hex | a4e3c19096f |
11331132000623 has 2 divisors, whose sum is σ = 11331132000624. Its totient is φ = 11331132000622.
The previous prime is 11331132000613. The next prime is 11331132000641. The reversal of 11331132000623 is 32600023113311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331132000623 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331132000592 and 11331132000601.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331132000613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000311 + 5665566000312.
It is an arithmetic number, because the mean of its divisors is an integer number (5665566000312).
Almost surely, 211331132000623 is an apocalyptic number.
11331132000623 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331132000623 is an equidigital number, since it uses as much as digits as its factorization.
11331132000623 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 11331132000623 its reverse (32600023113311), we get a palindrome (43931155113934).
The spelling of 11331132000623 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, six hundred twenty-three", and thus it is an aban number.
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