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11331132000623 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0110010000100101101111
31111010020122001221012100122
42210320330012100211233
52441122124243004443
640033241123315155
72246435004561131
oct244707406204557
944106561835318
1011331132000623
113679562681046
12133007121babb
136426a0cc11b6
142b26031d1051
15149b37049968
hexa4e3c19096f

11331132000623 has 2 divisors, whose sum is σ = 11331132000624. Its totient is φ = 11331132000622.

The previous prime is 11331132000613. The next prime is 11331132000641. The reversal of 11331132000623 is 32600023113311.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331132000623 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331132000592 and 11331132000601.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331132000613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000311 + 5665566000312.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566000312).

Almost surely, 211331132000623 is an apocalyptic number.

11331132000623 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132000623 is an equidigital number, since it uses as much as digits as its factorization.

11331132000623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 11331132000623 its reverse (32600023113311), we get a palindrome (43931155113934).

The spelling of 11331132000623 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, six hundred twenty-three", and thus it is an aban number.