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11331132000613 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0110010000100101100101
31111010020122001221012100021
42210320330012100211211
52441122124243004423
640033241123315141
72246435004561115
oct244707406204545
944106561835307
1011331132000613
113679562681037
12133007121bab1
136426a0cc11a9
142b26031d1045
15149b3704995d
hexa4e3c190965

11331132000613 has 2 divisors, whose sum is σ = 11331132000614. Its totient is φ = 11331132000612.

The previous prime is 11331132000583. The next prime is 11331132000623. The reversal of 11331132000613 is 31600023113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7291285256644 + 4039846743969 = 2700238^2 + 2009937^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331132000613 - 225 = 11331098446181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331132000623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000306 + 5665566000307.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566000307).

Almost surely, 211331132000613 is an apocalyptic number.

It is an amenable number.

11331132000613 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132000613 is an equidigital number, since it uses as much as digits as its factorization.

11331132000613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11331132000613 its reverse (31600023113311), we get a palindrome (42931155113924).

The spelling of 11331132000613 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, six hundred thirteen", and thus it is an aban number.