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11331132000997 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0110010000101011100101
31111010020122001221012212111
42210320330012100223211
52441122124243012442
640033241123321021
72246435004562204
oct244707406205345
944106561835774
1011331132000997
113679562681356
121330071220171
136426a0cc1413
142b26031d123b
15149b37049b17
hexa4e3c190ae5

11331132000997 has 2 divisors, whose sum is σ = 11331132000998. Its totient is φ = 11331132000996.

The previous prime is 11331132000989. The next prime is 11331132001037. The reversal of 11331132000997 is 79900023113311.

It is an a-pointer prime, because the next prime (11331132001037) can be obtained adding 11331132000997 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11116082778241 + 215049222756 = 3334079^2 + 463734^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331132000997 - 23 = 11331132000989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331132000497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000498 + 5665566000499.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566000499).

Almost surely, 211331132000997 is an apocalyptic number.

It is an amenable number.

11331132000997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132000997 is an equidigital number, since it uses as much as digits as its factorization.

11331132000997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30618, while the sum is 40.

The spelling of 11331132000997 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, nine hundred ninety-seven", and thus it is an aban number.