1133113200341 has 2 divisors, whose sum is σ = 1133113200342. Its totient is φ = 1133113200340.

The previous prime is 1133113200311. The next prime is 1133113200343. The reversal of 1133113200341 is 1430023113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 809442096100 + 323671104241 = 899690^2 + 568921^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133113200341 - 2¹⁴ = 1133113183957 is a prime.

Together with 1133113200343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133113200343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566556600170 + 566556600171.

It is an arithmetic number, because the mean of its divisors is an integer number (566556600171).

Almost surely, 2^{1133113200341} is an apocalyptic number.

It is an amenable number.

1133113200341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133113200341 is an equidigital number, since it uses as much as digits as its factorization.

1133113200341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1133113200341 its reverse (1430023113311), we get a palindrome (2563136313652).

The spelling of 1133113200341 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, two hundred thousand, three hundred forty-one".