1133113200433 has 2 divisors, whose sum is σ = 1133113200434. Its totient is φ = 1133113200432.

The previous prime is 1133113200431. The next prime is 1133113200467. The reversal of 1133113200433 is 3340023113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1038733987489 + 94379212944 = 1019183^2 + 307212^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133113200433 - 2¹ = 1133113200431 is a prime.

It is a super-4 number, since 4×1133113200433⁴ (a number of 49 digits) contains 4444 as substring.

Together with 1133113200431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1133113200398 and 1133113200407.

It is not a weakly prime, because it can be changed into another prime (1133113200431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566556600216 + 566556600217.

It is an arithmetic number, because the mean of its divisors is an integer number (566556600217).

Almost surely, 2^{1133113200433} is an apocalyptic number.

It is an amenable number.

1133113200433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133113200433 is an equidigital number, since it uses as much as digits as its factorization.

1133113200433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1133113200433 its reverse (3340023113311), we get a palindrome (4473136313744).

The spelling of 1133113200433 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, two hundred thousand, four hundred thirty-three".