Base | Representation |
---|---|
bin | 10000011111010011010… |
… | …011100111010010101101 |
3 | 11000022210012001222111221 |
4 | 100133103103213102231 |
5 | 122031113103024401 |
6 | 2224314314543341 |
7 | 144602544053665 |
oct | 20372323472255 |
9 | 4008705058457 |
10 | 1133121533101 |
11 | 3a7610624048 |
12 | 163734137b51 |
13 | 82b11a9757c |
14 | 3cbb43131a5 |
15 | 1e71d6787a1 |
hex | 107d34e74ad |
1133121533101 has 2 divisors, whose sum is σ = 1133121533102. Its totient is φ = 1133121533100.
The previous prime is 1133121533069. The next prime is 1133121533119. The reversal of 1133121533101 is 1013351213311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 884370968100 + 248750565001 = 940410^2 + 498749^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133121533101 - 25 = 1133121533069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133121593101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566560766550 + 566560766551.
It is an arithmetic number, because the mean of its divisors is an integer number (566560766551).
Almost surely, 21133121533101 is an apocalyptic number.
It is an amenable number.
1133121533101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133121533101 is an equidigital number, since it uses as much as digits as its factorization.
1133121533101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 25.
Adding to 1133121533101 its reverse (1013351213311), we get a palindrome (2146472746412).
The spelling of 1133121533101 in words is "one trillion, one hundred thirty-three billion, one hundred twenty-one million, five hundred thirty-three thousand, one hundred one".
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