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113312321431 is a prime number
BaseRepresentation
bin110100110000111110…
…0001100111110010111
3101211110221010100011121
41221201330030332113
53324030423241211
6124015512144411
711120661561151
oct1514174147627
9354427110147
10113312321431
1144067940241
1219b64098107
13a8ba80460a
1456ad089ad1
152e32cd1271
hex1a61f0cf97

113312321431 has 2 divisors, whose sum is σ = 113312321432. Its totient is φ = 113312321430.

The previous prime is 113312321411. The next prime is 113312321489. The reversal of 113312321431 is 134123213311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113312321431 - 25 = 113312321399 is a prime.

It is a super-2 number, since 2×1133123214312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113312321396 and 113312321405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113312321411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656160715 + 56656160716.

It is an arithmetic number, because the mean of its divisors is an integer number (56656160716).

Almost surely, 2113312321431 is an apocalyptic number.

113312321431 is a deficient number, since it is larger than the sum of its proper divisors (1).

113312321431 is an equidigital number, since it uses as much as digits as its factorization.

113312321431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 25.

Adding to 113312321431 its reverse (134123213311), we get a palindrome (247435534742).

The spelling of 113312321431 in words is "one hundred thirteen billion, three hundred twelve million, three hundred twenty-one thousand, four hundred thirty-one".