Base | Representation |
---|---|
bin | 10000011111010011011… |
… | …110101101110000010111 |
3 | 11000022210101112211100212 |
4 | 100133103132231300113 |
5 | 122031114324140114 |
6 | 2224314501200035 |
7 | 144602610564062 |
oct | 20372336556027 |
9 | 4008711484325 |
10 | 1133124443159 |
11 | 3a7612231455 |
12 | 16373510001b |
13 | 82b12575cb7 |
14 | 3cbb486d8d9 |
15 | 1e71da50b3e |
hex | 107d37adc17 |
1133124443159 has 2 divisors, whose sum is σ = 1133124443160. Its totient is φ = 1133124443158.
The previous prime is 1133124443131. The next prime is 1133124443161. The reversal of 1133124443159 is 9513444213311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1133124443159 - 28 = 1133124442903 is a prime.
Together with 1133124443161, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133124443179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566562221579 + 566562221580.
It is an arithmetic number, because the mean of its divisors is an integer number (566562221580).
Almost surely, 21133124443159 is an apocalyptic number.
1133124443159 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133124443159 is an equidigital number, since it uses as much as digits as its factorization.
1133124443159 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 155520, while the sum is 41.
The spelling of 1133124443159 in words is "one trillion, one hundred thirty-three billion, one hundred twenty-four million, four hundred forty-three thousand, one hundred fifty-nine".
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