Base | Representation |
---|---|
bin | 10101000110110010… |
… | …11110101111011111 |
3 | 1002020200211200211121 |
4 | 22203121132233133 |
5 | 141201303102234 |
6 | 5112221031411 |
7 | 550541314663 |
oct | 124331365737 |
9 | 32220750747 |
10 | 11331300319 |
11 | 4895250709 |
12 | 22429b5567 |
13 | 10b7764241 |
14 | 796cb08a3 |
15 | 464bd24b4 |
hex | 2a365ebdf |
11331300319 has 2 divisors, whose sum is σ = 11331300320. Its totient is φ = 11331300318.
The previous prime is 11331300287. The next prime is 11331300349. The reversal of 11331300319 is 91300313311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331300319 - 25 = 11331300287 is a prime.
It is a super-2 number, since 2×113313003192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11331300293 and 11331300302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331300349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665650159 + 5665650160.
It is an arithmetic number, because the mean of its divisors is an integer number (5665650160).
Almost surely, 211331300319 is an apocalyptic number.
11331300319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331300319 is an equidigital number, since it uses as much as digits as its factorization.
11331300319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 25.
The spelling of 11331300319 in words is "eleven billion, three hundred thirty-one million, three hundred thousand, three hundred nineteen".
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