Base | Representation |
---|---|
bin | 11001110000111011010000… |
… | …111010100000111010001111 |
3 | 112212012122111221122011211012 |
4 | 121300323100322200322033 |
5 | 104323011201021000101 |
6 | 1040555232015515435 |
7 | 32603422001536253 |
oct | 3160732072407217 |
9 | 485178457564735 |
10 | 113313332203151 |
11 | 33117a06a57783 |
12 | 10860a71828b7b |
13 | 4b2c52aa96462 |
14 | 1dda57489c263 |
15 | d17816cd7bbb |
hex | 670ed0ea0e8f |
113313332203151 has 2 divisors, whose sum is σ = 113313332203152. Its totient is φ = 113313332203150.
The previous prime is 113313332202991. The next prime is 113313332203207. The reversal of 113313332203151 is 151302233313311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113313332203151 - 210 = 113313332202127 is a prime.
It is a super-2 number, since 2×1133133322031512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113313332293151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656666101575 + 56656666101576.
It is an arithmetic number, because the mean of its divisors is an integer number (56656666101576).
Almost surely, 2113313332203151 is an apocalyptic number.
113313332203151 is a deficient number, since it is larger than the sum of its proper divisors (1).
113313332203151 is an equidigital number, since it uses as much as digits as its factorization.
113313332203151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 32.
Adding to 113313332203151 its reverse (151302233313311), we get a palindrome (264615565516462).
The spelling of 113313332203151 in words is "one hundred thirteen trillion, three hundred thirteen billion, three hundred thirty-two million, two hundred three thousand, one hundred fifty-one".
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