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113313332203151 is a prime number
BaseRepresentation
bin11001110000111011010000…
…111010100000111010001111
3112212012122111221122011211012
4121300323100322200322033
5104323011201021000101
61040555232015515435
732603422001536253
oct3160732072407217
9485178457564735
10113313332203151
1133117a06a57783
1210860a71828b7b
134b2c52aa96462
141dda57489c263
15d17816cd7bbb
hex670ed0ea0e8f

113313332203151 has 2 divisors, whose sum is σ = 113313332203152. Its totient is φ = 113313332203150.

The previous prime is 113313332202991. The next prime is 113313332203207. The reversal of 113313332203151 is 151302233313311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113313332203151 - 210 = 113313332202127 is a prime.

It is a super-2 number, since 2×1133133322031512 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113313332293151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656666101575 + 56656666101576.

It is an arithmetic number, because the mean of its divisors is an integer number (56656666101576).

Almost surely, 2113313332203151 is an apocalyptic number.

113313332203151 is a deficient number, since it is larger than the sum of its proper divisors (1).

113313332203151 is an equidigital number, since it uses as much as digits as its factorization.

113313332203151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14580, while the sum is 32.

Adding to 113313332203151 its reverse (151302233313311), we get a palindrome (264615565516462).

The spelling of 113313332203151 in words is "one hundred thirteen trillion, three hundred thirteen billion, three hundred thirty-two million, two hundred three thousand, one hundred fifty-one".