Base | Representation |
---|---|
bin | 1010010011100100110111… |
… | …1110110101001110001011 |
3 | 1111010021101222111221200012 |
4 | 2210321031332311032023 |
5 | 2441123233100342103 |
6 | 40033331002302135 |
7 | 2246445310106333 |
oct | 244711576651613 |
9 | 44107358457605 |
10 | 11331432043403 |
11 | 36796a6a8468a |
12 | 13301357b794b |
13 | 64271b2055c4 |
14 | 2b2630db60c3 |
15 | 149b535662d8 |
hex | a4e4dfb538b |
11331432043403 has 2 divisors, whose sum is σ = 11331432043404. Its totient is φ = 11331432043402.
The previous prime is 11331432043381. The next prime is 11331432043409. The reversal of 11331432043403 is 30434023413311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331432043403 - 242 = 6933385532299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11331432043403.
It is not a weakly prime, because it can be changed into another prime (11331432043409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665716021701 + 5665716021702.
It is an arithmetic number, because the mean of its divisors is an integer number (5665716021702).
Almost surely, 211331432043403 is an apocalyptic number.
11331432043403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331432043403 is an equidigital number, since it uses as much as digits as its factorization.
11331432043403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 11331432043403 its reverse (30434023413311), we get a palindrome (41765455456714).
The spelling of 11331432043403 in words is "eleven trillion, three hundred thirty-one billion, four hundred thirty-two million, forty-three thousand, four hundred three".
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