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113321305151 is a prime number
BaseRepresentation
bin110100110001001111…
…0011110010000111111
3101211111120000202111222
41221202132132100333
53324040223231101
6124020432503555
711121131125565
oct1514236362077
9354446022458
10113321305151
1144071a168aa
1219b670aabbb
13a8bc62b722
1456b0347a35
152e339a801b
hex1a6279e43f

113321305151 has 2 divisors, whose sum is σ = 113321305152. Its totient is φ = 113321305150.

The previous prime is 113321305073. The next prime is 113321305243. The reversal of 113321305151 is 151503123311.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (151503123311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113321305151 - 222 = 113317110847 is a prime.

It is a super-2 number, since 2×1133213051512 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113321305151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113321305051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660652575 + 56660652576.

It is an arithmetic number, because the mean of its divisors is an integer number (56660652576).

Almost surely, 2113321305151 is an apocalyptic number.

113321305151 is a deficient number, since it is larger than the sum of its proper divisors (1).

113321305151 is an equidigital number, since it uses as much as digits as its factorization.

113321305151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 26.

Adding to 113321305151 its reverse (151503123311), we get a palindrome (264824428462).

The spelling of 113321305151 in words is "one hundred thirteen billion, three hundred twenty-one million, three hundred five thousand, one hundred fifty-one".