Base | Representation |
---|---|
bin | 1010010011101000011111… |
… | …1011110110101000111000 |
3 | 1111010100220202001210122120 |
4 | 2210322013323312220320 |
5 | 2441132231002410204 |
6 | 40034011254121240 |
7 | 2246511354362154 |
oct | 244720773665070 |
9 | 44110822053576 |
10 | 11332404341304 |
11 | 367a0558a7472 |
12 | 1330367350220 |
13 | 6428447936c7 |
14 | 2b26c4192064 |
15 | 149badac46d9 |
hex | a4e87ef6a38 |
11332404341304 has 32 divisors (see below), whose sum is σ = 28331511976320. Its totient is φ = 3777401297376.
The previous prime is 11332404341299. The next prime is 11332404341351. The reversal of 11332404341304 is 40314340423311.
It is a super-2 number, since 2×113324043413042 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2781412 + ... + 5513715.
It is an arithmetic number, because the mean of its divisors is an integer number (885359749260).
Almost surely, 211332404341304 is an apocalyptic number.
It is an amenable number.
11332404341304 is an abundant number, since it is smaller than the sum of its proper divisors (16999107635016).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11332404341304 is a wasteful number, since it uses less digits than its factorization.
11332404341304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8352059 (or 8352055 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 11332404341304 its reverse (40314340423311), we get a palindrome (51646744764615).
The spelling of 11332404341304 in words is "eleven trillion, three hundred thirty-two billion, four hundred four million, three hundred forty-one thousand, three hundred four".
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