Base | Representation |
---|---|
bin | 10000011111100011111… |
… | …111001110011101110000 |
3 | 11000100111200200202101002 |
4 | 100133203333032131300 |
5 | 122032201224314300 |
6 | 2224402153301132 |
7 | 144612512644655 |
oct | 20374377163560 |
9 | 4010450622332 |
10 | 1133401401200 |
11 | 3a77445a80a2 |
12 | 1637b1a047a8 |
13 | 82b57a66bb3 |
14 | 3cbdd565c2c |
15 | 1e73800c5d5 |
hex | 107e3fce770 |
1133401401200 has 60 divisors (see below), whose sum is σ = 2727206139600. Its totient is φ = 452659745280.
The previous prime is 1133401401157. The next prime is 1133401401269. The reversal of 1133401401200 is 21041043311.
It is a super-2 number, since 2×11334014012002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1930925 + ... + 2448524.
It is an arithmetic number, because the mean of its divisors is an integer number (45453435660).
Almost surely, 21133401401200 is an apocalyptic number.
1133401401200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1133401401200 is an abundant number, since it is smaller than the sum of its proper divisors (1593804738400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1133401401200 is a wasteful number, since it uses less digits than its factorization.
1133401401200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4380114 (or 4380103 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1133401401200 its reverse (21041043311), we get a palindrome (1154442444511).
The spelling of 1133401401200 in words is "one trillion, one hundred thirty-three billion, four hundred one million, four hundred one thousand, two hundred".
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