Base | Representation |
---|---|
bin | 10000011111100110011… |
… | …010100110110010011111 |
3 | 11000100121112100011002212 |
4 | 100133212122212302133 |
5 | 122032242141230101 |
6 | 2224410210311035 |
7 | 144613516112006 |
oct | 20374632466237 |
9 | 4010545304085 |
10 | 1133442133151 |
11 | 3a7765598669 |
12 | 16380358847b |
13 | 82b63328943 |
14 | 3cc04b29c3d |
15 | 1e73b8a61bb |
hex | 107e66a6c9f |
1133442133151 has 2 divisors, whose sum is σ = 1133442133152. Its totient is φ = 1133442133150.
The previous prime is 1133442133127. The next prime is 1133442133171. The reversal of 1133442133151 is 1513312443311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1133442133151 - 210 = 1133442132127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133442133111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566721066575 + 566721066576.
It is an arithmetic number, because the mean of its divisors is an integer number (566721066576).
Almost surely, 21133442133151 is an apocalyptic number.
1133442133151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133442133151 is an equidigital number, since it uses as much as digits as its factorization.
1133442133151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12960, while the sum is 32.
Adding to 1133442133151 its reverse (1513312443311), we get a palindrome (2646754576462).
The spelling of 1133442133151 in words is "one trillion, one hundred thirty-three billion, four hundred forty-two million, one hundred thirty-three thousand, one hundred fifty-one".
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