113351544149 has 2 divisors, whose sum is σ = 113351544150. Its totient is φ = 113351544148.

The previous prime is 113351544083. The next prime is 113351544151. The reversal of 113351544149 is 941445153311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59930467249 + 53421076900 = 244807^2 + 231130^2 .

It is a cyclic number.

It is not a de Polignac number, because 113351544149 - 2¹² = 113351540053 is a prime.

It is a super-2 number, since 2×113351544149² (a number of 23 digits) contains 22 as substring.

Together with 113351544151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113351544749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56675772074 + 56675772075.

It is an arithmetic number, because the mean of its divisors is an integer number (56675772075).

Almost surely, 2^113351544149 is an apocalyptic number.

It is an amenable number.

113351544149 is a deficient number, since it is larger than the sum of its proper divisors (1).

113351544149 is an equidigital number, since it uses as much as digits as its factorization.

113351544149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129600, while the sum is 41.

The spelling of 113351544149 in words is "one hundred thirteen billion, three hundred fifty-one million, five hundred forty-four thousand, one hundred forty-nine".