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113367543437 is a prime number
BaseRepresentation
bin110100110010100111…
…0110110111010001101
3101211121210000220112002
41221211032312322031
53324134042342222
6124025203522045
711122232135231
oct1514516667215
9354553026462
10113367543437
1144096028365
1219b7a689325
13a8c909a865
1456b65425c1
152e37a8d392
hex1a653b6e8d

113367543437 has 2 divisors, whose sum is σ = 113367543438. Its totient is φ = 113367543436.

The previous prime is 113367543407. The next prime is 113367543451. The reversal of 113367543437 is 734345763311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57018753796 + 56348789641 = 238786^2 + 237379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113367543437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113367543391 and 113367543400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113367543407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56683771718 + 56683771719.

It is an arithmetic number, because the mean of its divisors is an integer number (56683771719).

Almost surely, 2113367543437 is an apocalyptic number.

It is an amenable number.

113367543437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113367543437 is an equidigital number, since it uses as much as digits as its factorization.

113367543437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1905120, while the sum is 47.

The spelling of 113367543437 in words is "one hundred thirteen billion, three hundred sixty-seven million, five hundred forty-three thousand, four hundred thirty-seven".