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1134051350447 is a prime number
BaseRepresentation
bin10000100000001010101…
…110100101011110101111
311000102011222200121010102
4100200022232211132233
5122040014121203242
62224550452101315
7144634564300511
oct20401256453657
94012158617112
101134051350447
113a7a48471634
1216395360483b
1382c2c600a52
143cc619d1bb1
151e7750e4e32
hex1080aba57af

1134051350447 has 2 divisors, whose sum is σ = 1134051350448. Its totient is φ = 1134051350446.

The previous prime is 1134051350407. The next prime is 1134051350527. The reversal of 1134051350447 is 7440531504311.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1134051350447 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1134051350447.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1134051350407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567025675223 + 567025675224.

It is an arithmetic number, because the mean of its divisors is an integer number (567025675224).

Almost surely, 21134051350447 is an apocalyptic number.

1134051350447 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134051350447 is an equidigital number, since it uses as much as digits as its factorization.

1134051350447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100800, while the sum is 38.

Adding to 1134051350447 its reverse (7440531504311), we get a palindrome (8574582854758).

The spelling of 1134051350447 in words is "one trillion, one hundred thirty-four billion, fifty-one million, three hundred fifty thousand, four hundred forty-seven".