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113413141141 is a prime number
BaseRepresentation
bin110100110011111110…
…0110011001010010101
3101211201221211111210221
41221213330303022111
53324232231004031
6124033513114341
711123324536156
oct1514774631225
9354657744727
10113413141141
1144109841613
1219b919b89b1
13a905674251
1456bc61192d
152e3ba98a11
hex1a67f33295

113413141141 has 2 divisors, whose sum is σ = 113413141142. Its totient is φ = 113413141140.

The previous prime is 113413141123. The next prime is 113413141201. The reversal of 113413141141 is 141141314311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97113256900 + 16299884241 = 311630^2 + 127671^2 .

It is a cyclic number.

It is not a de Polignac number, because 113413141141 - 211 = 113413139093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113413141241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56706570570 + 56706570571.

It is an arithmetic number, because the mean of its divisors is an integer number (56706570571).

Almost surely, 2113413141141 is an apocalyptic number.

It is an amenable number.

113413141141 is a deficient number, since it is larger than the sum of its proper divisors (1).

113413141141 is an equidigital number, since it uses as much as digits as its factorization.

113413141141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 25.

Adding to 113413141141 its reverse (141141314311), we get a palindrome (254554455452).

The spelling of 113413141141 in words is "one hundred thirteen billion, four hundred thirteen million, one hundred forty-one thousand, one hundred forty-one".