Base | Representation |
---|---|
bin | 10101001000000001… |
… | …00110010110111100 |
3 | 1002021102010200210111 |
4 | 22210000212112330 |
5 | 141211414231012 |
6 | 5113224515404 |
7 | 551024425255 |
oct | 124400462674 |
9 | 32242120714 |
10 | 11341555132 |
11 | 48a0015266 |
12 | 224631bb64 |
13 | 10b9914a8b |
14 | 7983bdb2c |
15 | 465a5aba7 |
hex | 2a40265bc |
11341555132 has 24 divisors (see below), whose sum is σ = 20880140400. Its totient is φ = 5382429696.
The previous prime is 11341555109. The next prime is 11341555133. The reversal of 11341555132 is 23155514311.
It is a junction number, because it is equal to n+sod(n) for n = 11341555094 and 11341555103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11341555133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 821733 + ... + 835420.
It is an arithmetic number, because the mean of its divisors is an integer number (870005850).
Almost surely, 211341555132 is an apocalyptic number.
It is an amenable number.
11341555132 is a deficient number, since it is larger than the sum of its proper divisors (9538585268).
11341555132 is a wasteful number, since it uses less digits than its factorization.
11341555132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1657245 (or 1657243 counting only the distinct ones).
The product of its digits is 9000, while the sum is 31.
It can be divided in two parts, 11 and 341555132, that added together give a palindrome (341555143).
The spelling of 11341555132 in words is "eleven billion, three hundred forty-one million, five hundred fifty-five thousand, one hundred thirty-two".
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