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113420241113083 is a prime number
BaseRepresentation
bin11001110010011110110101…
…001011101000111111111011
3112212120212110121121111202221
4121302132311023220333323
5104331234123211104313
61041120312304504511
732614225210351312
oct3162366513507773
9485525417544687
10113420241113083
11331592882810a3
121087972931b137
134b39637a67988
1420017d7327279
15d1a4c2846c8d
hex6727b52e8ffb

113420241113083 has 2 divisors, whose sum is σ = 113420241113084. Its totient is φ = 113420241113082.

The previous prime is 113420241113077. The next prime is 113420241113117. The reversal of 113420241113083 is 380311142024311.

It is an a-pointer prime, because the next prime (113420241113117) can be obtained adding 113420241113083 to its sum of digits (34).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113420241113083 is a prime.

It is not a weakly prime, because it can be changed into another prime (113420241110083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56710120556541 + 56710120556542.

It is an arithmetic number, because the mean of its divisors is an integer number (56710120556542).

Almost surely, 2113420241113083 is an apocalyptic number.

113420241113083 is a deficient number, since it is larger than the sum of its proper divisors (1).

113420241113083 is an equidigital number, since it uses as much as digits as its factorization.

113420241113083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 34.

Adding to 113420241113083 its reverse (380311142024311), we get a palindrome (493731383137394).

The spelling of 113420241113083 in words is "one hundred thirteen trillion, four hundred twenty billion, two hundred forty-one million, one hundred thirteen thousand, eighty-three".