Base | Representation |
---|---|
bin | 110100110100001011… |
… | …1111000101000001101 |
3 | 101211202110012020120021 |
4 | 1221220113320220031 |
5 | 3324241040211141 |
6 | 124034325222141 |
7 | 11123442100534 |
oct | 1515027705015 |
9 | 354673166507 |
10 | 113420241421 |
11 | 44112851113 |
12 | 19b94261951 |
13 | a906c8bcb6 |
14 | 56bd53d31b |
15 | 2e3c4ec6d1 |
hex | 1a685f8a0d |
113420241421 has 2 divisors, whose sum is σ = 113420241422. Its totient is φ = 113420241420.
The previous prime is 113420241377. The next prime is 113420241443. The reversal of 113420241421 is 124142024311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112569644196 + 850597225 = 335514^2 + 29165^2 .
It is a cyclic number.
It is not a de Polignac number, because 113420241421 - 213 = 113420233229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113420241491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56710120710 + 56710120711.
It is an arithmetic number, because the mean of its divisors is an integer number (56710120711).
Almost surely, 2113420241421 is an apocalyptic number.
It is an amenable number.
113420241421 is a deficient number, since it is larger than the sum of its proper divisors (1).
113420241421 is an equidigital number, since it uses as much as digits as its factorization.
113420241421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 113420241421 its reverse (124142024311), we get a palindrome (237562265732).
The spelling of 113420241421 in words is "one hundred thirteen billion, four hundred twenty million, two hundred forty-one thousand, four hundred twenty-one".
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