1134214000001 has 2 divisors, whose sum is σ = 1134214000002. Its totient is φ = 1134214000000.

The previous prime is 1134213999973. The next prime is 1134214000009. The reversal of 1134214000001 is 1000004124311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 625593993025 + 508620006976 = 790945^2 + 713176^2 .

It is an emirp because it is prime and its reverse (1000004124311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1134214000001 is a prime.

It is not a weakly prime, because it can be changed into another prime (1134214000009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567107000000 + 567107000001.

It is an arithmetic number, because the mean of its divisors is an integer number (567107000001).

Almost surely, 2^{1134214000001} is an apocalyptic number.

It is an amenable number.

1134214000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134214000001 is an equidigital number, since it uses as much as digits as its factorization.

1134214000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1134214000001 its reverse (1000004124311), we get a palindrome (2134218124312).

The spelling of 1134214000001 in words is "one trillion, one hundred thirty-four billion, two hundred fourteen million, one", and thus it is an aban number.