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113431107557 is a prime number
BaseRepresentation
bin110100110100100000…
…1010101011111100101
3101211210012122022002202
41221221001111133211
53324301330420212
6124035354144245
711123633335325
oct1515101253745
9354705568082
10113431107557
11441189a2a99
1219b97a22085
13a9092c4b71
1456c0b6b285
152e3d4470c2
hex1a690557e5

113431107557 has 2 divisors, whose sum is σ = 113431107558. Its totient is φ = 113431107556.

The previous prime is 113431107541. The next prime is 113431107583. The reversal of 113431107557 is 755701134311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98449102756 + 14982004801 = 313766^2 + 122401^2 .

It is a cyclic number.

It is not a de Polignac number, because 113431107557 - 24 = 113431107541 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113431107557.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113431103557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56715553778 + 56715553779.

It is an arithmetic number, because the mean of its divisors is an integer number (56715553779).

Almost surely, 2113431107557 is an apocalyptic number.

It is an amenable number.

113431107557 is a deficient number, since it is larger than the sum of its proper divisors (1).

113431107557 is an equidigital number, since it uses as much as digits as its factorization.

113431107557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 44100, while the sum is 38.

The spelling of 113431107557 in words is "one hundred thirteen billion, four hundred thirty-one million, one hundred seven thousand, five hundred fifty-seven".