Base | Representation |
---|---|
bin | 110100110100100010… |
… | …1100011111001011101 |
3 | 101211210021201120102002 |
4 | 1221221011203321131 |
5 | 3324302121341013 |
6 | 124035434012045 |
7 | 11123645630366 |
oct | 1515105437135 |
9 | 354707646362 |
10 | 113432215133 |
11 | 4411958a146 |
12 | 19b98277025 |
13 | a9095c2033 |
14 | 56c0d78b6d |
15 | 2e3d5b5358 |
hex | 1a69163e5d |
113432215133 has 2 divisors, whose sum is σ = 113432215134. Its totient is φ = 113432215132.
The previous prime is 113432215129. The next prime is 113432215151. The reversal of 113432215133 is 331512234311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113355442489 + 76772644 = 336683^2 + 8762^2 .
It is a cyclic number.
It is not a de Polignac number, because 113432215133 - 22 = 113432215129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113432215096 and 113432215105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113432215123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716107566 + 56716107567.
It is an arithmetic number, because the mean of its divisors is an integer number (56716107567).
Almost surely, 2113432215133 is an apocalyptic number.
It is an amenable number.
113432215133 is a deficient number, since it is larger than the sum of its proper divisors (1).
113432215133 is an equidigital number, since it uses as much as digits as its factorization.
113432215133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 29.
Adding to 113432215133 its reverse (331512234311), we get a palindrome (444944449444).
The spelling of 113432215133 in words is "one hundred thirteen billion, four hundred thirty-two million, two hundred fifteen thousand, one hundred thirty-three".
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