Base | Representation |
---|---|
bin | 1101100001011… |
… | …01101000110111 |
3 | 21220110000000112 |
4 | 12300231220313 |
5 | 213014330033 |
6 | 15131133235 |
7 | 2545110605 |
oct | 660555067 |
9 | 256400015 |
10 | 113433143 |
11 | 59036aaa |
12 | 31ba421b |
13 | 1a667c05 |
14 | 110ca875 |
15 | 9e59c48 |
hex | 6c2da37 |
113433143 has 2 divisors, whose sum is σ = 113433144. Its totient is φ = 113433142.
The previous prime is 113433127. The next prime is 113433149. The reversal of 113433143 is 341334311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113433143 - 24 = 113433127 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113433149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716571 + 56716572.
It is an arithmetic number, because the mean of its divisors is an integer number (56716572).
Almost surely, 2113433143 is an apocalyptic number.
113433143 is a deficient number, since it is larger than the sum of its proper divisors (1).
113433143 is an equidigital number, since it uses as much as digits as its factorization.
113433143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 23.
The square root of 113433143 is about 10650.4996596404. The cubic root of 113433143 is about 484.0757442985.
Adding to 113433143 its reverse (341334311), we get a palindrome (454767454).
The spelling of 113433143 in words is "one hundred thirteen million, four hundred thirty-three thousand, one hundred forty-three".
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