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113433127 is a prime number
BaseRepresentation
bin1101100001011…
…01101000100111
321220102222222221
412300231220213
5213014330002
615131133211
72545110553
oct660555047
9256388887
10113433127
1159036a95
1231ba4207
131a667bc2
14110ca863
159e59c37
hex6c2da27

113433127 has 2 divisors, whose sum is σ = 113433128. Its totient is φ = 113433126.

The previous prime is 113433121. The next prime is 113433143. The reversal of 113433127 is 721334311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113433127 - 23 = 113433119 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113433121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716563 + 56716564.

It is an arithmetic number, because the mean of its divisors is an integer number (56716564).

Almost surely, 2113433127 is an apocalyptic number.

113433127 is a deficient number, since it is larger than the sum of its proper divisors (1).

113433127 is an equidigital number, since it uses as much as digits as its factorization.

113433127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1512, while the sum is 25.

The square root of 113433127 is about 10650.4989085019. The cubic root of 113433127 is about 484.0757215385.

Adding to 113433127 its reverse (721334311), we get a palindrome (834767438).

The spelling of 113433127 in words is "one hundred thirteen million, four hundred thirty-three thousand, one hundred twenty-seven".