Base | Representation |
---|---|
bin | 110100110100100100… |
… | …1101101010100011100 |
3 | 101211210100202210201112 |
4 | 1221221021231110130 |
5 | 3324302411133200 |
6 | 124035513201152 |
7 | 11123661106103 |
oct | 1515111552434 |
9 | 354710683645 |
10 | 113433302300 |
11 | 4411a161a2a |
12 | 19b987001b8 |
13 | a9098b2b26 |
14 | 56c117d03a |
15 | 2e3d72c535 |
hex | 1a6926d51c |
113433302300 has 36 divisors (see below), whose sum is σ = 246179566416. Its totient is φ = 45367920000.
The previous prime is 113433302293. The next prime is 113433302309. The reversal of 113433302300 is 3203334311.
It is a super-2 number, since 2×1134333023002 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113433302309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 837089 + ... + 963111.
Almost surely, 2113433302300 is an apocalyptic number.
113433302300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113433302300 is an abundant number, since it is smaller than the sum of its proper divisors (132746264116).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113433302300 is a wasteful number, since it uses less digits than its factorization.
113433302300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135038 (or 135031 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 113433302300 its reverse (3203334311), we get a palindrome (116636636611).
The spelling of 113433302300 in words is "one hundred thirteen billion, four hundred thirty-three million, three hundred two thousand, three hundred".
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