113433302400 has 768 divisors, whose sum is σ = 435202502400. Its totient is φ = 25663897600.

The previous prime is 113433302369. The next prime is 113433302401. The reversal of 113433302400 is 4203334311.

113433302400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×113433302400² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113433302401) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 321340624 + ... + 321340976.

It is an arithmetic number, because the mean of its divisors is an integer number (566669925).

Almost surely, 2^113433302400 is an apocalyptic number.

113433302400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113433302400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217601251200).

113433302400 is an abundant number, since it is smaller than the sum of its proper divisors (321769200000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113433302400 is a wasteful number, since it uses less digits than its factorization.

113433302400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 587 (or 570 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 113433302400 its reverse (4203334311), we get a palindrome (117636636711).

The spelling of 113433302400 in words is "one hundred thirteen billion, four hundred thirty-three million, three hundred two thousand, four hundred".