1134401300130 has 64 divisors (see below), whose sum is σ = 3116097112320. Its totient is φ = 258908692224.

The previous prime is 1134401300117. The next prime is 1134401300189. The reversal of 1134401300130 is 310031044311.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 1134401300097 and 1134401300106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3847425 + ... + 4131764.

It is an arithmetic number, because the mean of its divisors is an integer number (48689017380).

Almost surely, 2^{1134401300130} is an apocalyptic number.

1134401300130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1134401300130 is an abundant number, since it is smaller than the sum of its proper divisors (1981695812190).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1134401300130 is a wasteful number, since it uses less digits than its factorization.

1134401300130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7979883.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1134401300130 its reverse (310031044311), we get a palindrome (1444432344441).

The spelling of 1134401300130 in words is "one trillion, one hundred thirty-four billion, four hundred one million, three hundred thousand, one hundred thirty".