Base | Representation |
---|---|
bin | 10101001000010101… |
… | …01110110011000111 |
3 | 1002021121010122011021 |
4 | 22210022232303013 |
5 | 141213104224033 |
6 | 5113401452011 |
7 | 551056126606 |
oct | 124412566307 |
9 | 32247118137 |
10 | 11344211143 |
11 | 48a1569811 |
12 | 22471a1007 |
13 | 10ba334995 |
14 | 7988b1a3d |
15 | 465dd2b2d |
hex | 2a42aecc7 |
11344211143 has 2 divisors, whose sum is σ = 11344211144. Its totient is φ = 11344211142.
The previous prime is 11344211101. The next prime is 11344211167. The reversal of 11344211143 is 34111244311.
11344211143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11344211143 - 229 = 10807340231 is a prime.
It is a super-2 number, since 2×113442111432 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11344211243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672105571 + 5672105572.
It is an arithmetic number, because the mean of its divisors is an integer number (5672105572).
Almost surely, 211344211143 is an apocalyptic number.
11344211143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344211143 is an equidigital number, since it uses as much as digits as its factorization.
11344211143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152, while the sum is 25.
Adding to 11344211143 its reverse (34111244311), we get a palindrome (45455455454).
The spelling of 11344211143 in words is "eleven billion, three hundred forty-four million, two hundred eleven thousand, one hundred forty-three".
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