Base | Representation |
---|---|
bin | 1010010100010100111011… |
… | …0100011111111111111101 |
3 | 1111011111200221012120001011 |
4 | 2211011032310133333331 |
5 | 2441331142214423031 |
6 | 40043302544115221 |
7 | 2250413045414116 |
oct | 245051664377775 |
9 | 44144627176034 |
10 | 11344331014141 |
11 | 3684116125284 |
12 | 1332735605b11 |
13 | 6439c5693178 |
14 | 2b30d616320d |
15 | 14a15abad6b1 |
hex | a514ed1fffd |
11344331014141 has 2 divisors, whose sum is σ = 11344331014142. Its totient is φ = 11344331014140.
The previous prime is 11344331014127. The next prime is 11344331014169. The reversal of 11344331014141 is 14141013344311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6060902372100 + 5283428642041 = 2461890^2 + 2298571^2 .
It is a cyclic number.
It is not a de Polignac number, because 11344331014141 - 211 = 11344331012093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11344331014171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672165507070 + 5672165507071.
It is an arithmetic number, because the mean of its divisors is an integer number (5672165507071).
Almost surely, 211344331014141 is an apocalyptic number.
It is an amenable number.
11344331014141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344331014141 is an equidigital number, since it uses as much as digits as its factorization.
11344331014141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 11344331014141 its reverse (14141013344311), we get a palindrome (25485344358452).
The spelling of 11344331014141 in words is "eleven trillion, three hundred forty-four billion, three hundred thirty-one million, fourteen thousand, one hundred forty-one".
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