Base | Representation |
---|---|
bin | 10101001000010110… |
… | …11101011111110111 |
3 | 1002021121111100112201 |
4 | 22210023131133313 |
5 | 141213131334143 |
6 | 5113405525331 |
7 | 551060554354 |
oct | 124413353767 |
9 | 32247440481 |
10 | 11344402423 |
11 | 48a168a4a2 |
12 | 2247273847 |
13 | 10ba3a0a73 |
14 | 79892162b |
15 | 465e1e64d |
hex | 2a42dd7f7 |
11344402423 has 2 divisors, whose sum is σ = 11344402424. Its totient is φ = 11344402422.
The previous prime is 11344402397. The next prime is 11344402451. The reversal of 11344402423 is 32420444311.
It is an a-pointer prime, because the next prime (11344402451) can be obtained adding 11344402423 to its sum of digits (28).
It is a weak prime.
It is an emirp because it is prime and its reverse (32420444311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11344402423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11344402391 and 11344402400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11344409423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672201211 + 5672201212.
It is an arithmetic number, because the mean of its divisors is an integer number (5672201212).
Almost surely, 211344402423 is an apocalyptic number.
11344402423 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344402423 is an equidigital number, since it uses as much as digits as its factorization.
11344402423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 11344402423 its reverse (32420444311), we get a palindrome (43764846734).
The spelling of 11344402423 in words is "eleven billion, three hundred forty-four million, four hundred two thousand, four hundred twenty-three".
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