113444221413143 has 2 divisors, whose sum is σ = 113444221413144. Its totient is φ = 113444221413142.

The previous prime is 113444221413031. The next prime is 113444221413247. The reversal of 113444221413143 is 341314122444311.

It is a strong prime.

It is an emirp because it is prime and its reverse (341314122444311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113444221413143 - 2¹⁶ = 113444221347607 is a prime.

It is a super-3 number, since 3×113444221413143³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113444221413097 and 113444221413106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113444226413143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56722110706571 + 56722110706572.

It is an arithmetic number, because the mean of its divisors is an integer number (56722110706572).

Almost surely, 2^{113444221413143} is an apocalyptic number.

113444221413143 is a deficient number, since it is larger than the sum of its proper divisors (1).

113444221413143 is an equidigital number, since it uses as much as digits as its factorization.

113444221413143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 110592, while the sum is 38.

Adding to 113444221413143 its reverse (341314122444311), we get a palindrome (454758343857454).

The spelling of 113444221413143 in words is "one hundred thirteen trillion, four hundred forty-four billion, two hundred twenty-one million, four hundred thirteen thousand, one hundred forty-three".