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1134443143 is a prime number
BaseRepresentation
bin100001110011110…
…0011101010000111
32221001122200102201
41003213203222013
54310404140033
6304323015331
740053415261
oct10347435207
92831580381
101134443143
115323aaa19
12277b0a547
13151050142
14aa946b31
15698db47d
hex439e3a87

1134443143 has 2 divisors, whose sum is σ = 1134443144. Its totient is φ = 1134443142.

The previous prime is 1134443131. The next prime is 1134443173. The reversal of 1134443143 is 3413444311.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (3413444311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1134443143 is a prime.

It is a super-2 number, since 2×11344431432 = 2573922489399436898, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1134443173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567221571 + 567221572.

It is an arithmetic number, because the mean of its divisors is an integer number (567221572).

Almost surely, 21134443143 is an apocalyptic number.

1134443143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134443143 is an equidigital number, since it uses as much as digits as its factorization.

1134443143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 28.

The square root of 1134443143 is about 33681.4955576500. The cubic root of 1134443143 is about 1042.9438114792.

Adding to 1134443143 its reverse (3413444311), we get a palindrome (4547887454).

The spelling of 1134443143 in words is "one billion, one hundred thirty-four million, four hundred forty-three thousand, one hundred forty-three".