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113463744165341 is a prime number
BaseRepresentation
bin11001110011000111010110…
…001010100111010111011101
3112212202000202102021112120122
4121303013112022213113131
5104332442222001242331
61041152305142124325
732620325232243413
oct3163072612472735
9485660672245518
10113463744165341
1133175781651149
121088604a4206a5
134b4077b7b4c0b
142003962c492b3
15d1b6bbb4017b
hex6731d62a75dd

113463744165341 has 2 divisors, whose sum is σ = 113463744165342. Its totient is φ = 113463744165340.

The previous prime is 113463744165329. The next prime is 113463744165361. The reversal of 113463744165341 is 143561447364311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104726671296025 + 8737072869316 = 10233605^2 + 2955854^2 .

It is an emirp because it is prime and its reverse (143561447364311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113463744165341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113463744165361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56731872082670 + 56731872082671.

It is an arithmetic number, because the mean of its divisors is an integer number (56731872082671).

Almost surely, 2113463744165341 is an apocalyptic number.

It is an amenable number.

113463744165341 is a deficient number, since it is larger than the sum of its proper divisors (1).

113463744165341 is an equidigital number, since it uses as much as digits as its factorization.

113463744165341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8709120, while the sum is 53.

The spelling of 113463744165341 in words is "one hundred thirteen trillion, four hundred sixty-three billion, seven hundred forty-four million, one hundred sixty-five thousand, three hundred forty-one".