Base | Representation |
---|---|
bin | 10101001001000010… |
… | …10010101101111001 |
3 | 1002022000021010001001 |
4 | 22210201102231321 |
5 | 141221113003213 |
6 | 5114132325001 |
7 | 551160321463 |
oct | 124441225571 |
9 | 32260233031 |
10 | 11350125433 |
11 | 48a4939259 |
12 | 2249173761 |
13 | 10bb62596a |
14 | 7995b1133 |
15 | 4666a01dd |
hex | 2a4852b79 |
11350125433 has 2 divisors, whose sum is σ = 11350125434. Its totient is φ = 11350125432.
The previous prime is 11350125431. The next prime is 11350125443. The reversal of 11350125433 is 33452105311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10830148624 + 519976809 = 104068^2 + 22803^2 .
It is an emirp because it is prime and its reverse (33452105311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11350125433 - 21 = 11350125431 is a prime.
Together with 11350125431, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11350125431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5675062716 + 5675062717.
It is an arithmetic number, because the mean of its divisors is an integer number (5675062717).
Almost surely, 211350125433 is an apocalyptic number.
It is an amenable number.
11350125433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11350125433 is an equidigital number, since it uses as much as digits as its factorization.
11350125433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
The spelling of 11350125433 in words is "eleven billion, three hundred fifty million, one hundred twenty-five thousand, four hundred thirty-three".
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