Base | Representation |
---|---|
bin | 10101001001001010… |
… | …01000000011000111 |
3 | 1002022002011011110202 |
4 | 22210211020003013 |
5 | 141221342132221 |
6 | 5114210041115 |
7 | 551202005243 |
oct | 124445100307 |
9 | 32262134422 |
10 | 11351130311 |
11 | 48a5465234 |
12 | 224957919b |
13 | 10bb8b8171 |
14 | 799793423 |
15 | 4667ecd0b |
hex | 2a49480c7 |
11351130311 has 2 divisors, whose sum is σ = 11351130312. Its totient is φ = 11351130310.
The previous prime is 11351130253. The next prime is 11351130313. The reversal of 11351130311 is 11303115311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11351130311 - 210 = 11351129287 is a prime.
It is a super-4 number, since 4×113511303114 (a number of 41 digits) contains 4444 as substring.
Together with 11351130313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11351130313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5675565155 + 5675565156.
It is an arithmetic number, because the mean of its divisors is an integer number (5675565156).
Almost surely, 211351130311 is an apocalyptic number.
11351130311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11351130311 is an equidigital number, since it uses as much as digits as its factorization.
11351130311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 135, while the sum is 20.
Adding to 11351130311 its reverse (11303115311), we get a palindrome (22654245622).
The spelling of 11351130311 in words is "eleven billion, three hundred fifty-one million, one hundred thirty thousand, three hundred eleven".
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