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1135200412573 is a prime number
BaseRepresentation
bin10000100001001111001…
…101111010001110011101
311000112011001212000000221
4100201033031322032131
5122044342301200243
62225300500321341
7145005216204043
oct20411715721635
94015131760027
101135200412573
113a8488046a57
121640143a3251
138308369bc76
143cd30462393
151e7e0e1cbed
hex1084f37a39d

1135200412573 has 2 divisors, whose sum is σ = 1135200412574. Its totient is φ = 1135200412572.

The previous prime is 1135200412543. The next prime is 1135200412583. The reversal of 1135200412573 is 3752140025311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1084893062724 + 50307349849 = 1041582^2 + 224293^2 .

It is an emirp because it is prime and its reverse (3752140025311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1135200412573 - 225 = 1135166858141 is a prime.

It is a super-3 number, since 3×11352004125733 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1135200412523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567600206286 + 567600206287.

It is an arithmetic number, because the mean of its divisors is an integer number (567600206287).

Almost surely, 21135200412573 is an apocalyptic number.

It is an amenable number.

1135200412573 is a deficient number, since it is larger than the sum of its proper divisors (1).

1135200412573 is an equidigital number, since it uses as much as digits as its factorization.

1135200412573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 34.

Adding to 1135200412573 its reverse (3752140025311), we get a palindrome (4887340437884).

The spelling of 1135200412573 in words is "one trillion, one hundred thirty-five billion, two hundred million, four hundred twelve thousand, five hundred seventy-three".