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113534524205477 is a prime number
BaseRepresentation
bin11001110100001001010000…
…111111000010100110100101
3112212222210110012102010100122
4121310021100333002212211
5104340122201144033402
61041245012420051325
732625412230535514
oct3164112077024645
9485883405363318
10113534524205477
11331a27a3090991
1210897902533b45
134b4734b71437b
1420071592b267b
15d1d460983ca2
hex674250fc29a5

113534524205477 has 2 divisors, whose sum is σ = 113534524205478. Its totient is φ = 113534524205476.

The previous prime is 113534524205329. The next prime is 113534524205527. The reversal of 113534524205477 is 774502425435311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111879825310276 + 1654698895201 = 10577326^2 + 1286351^2 .

It is a cyclic number.

It is not a de Polignac number, because 113534524205477 - 218 = 113534523943333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113534524205177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767262102738 + 56767262102739.

It is an arithmetic number, because the mean of its divisors is an integer number (56767262102739).

Almost surely, 2113534524205477 is an apocalyptic number.

It is an amenable number.

113534524205477 is a deficient number, since it is larger than the sum of its proper divisors (1).

113534524205477 is an equidigital number, since it uses as much as digits as its factorization.

113534524205477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14112000, while the sum is 53.

The spelling of 113534524205477 in words is "one hundred thirteen trillion, five hundred thirty-four billion, five hundred twenty-four million, two hundred five thousand, four hundred seventy-seven".