Base | Representation |
---|---|
bin | 11001110100001110011110… |
… | …000010111001111010101100 |
3 | 112220000022212121220002111110 |
4 | 121310032132002321322230 |
5 | 104340220122140001104 |
6 | 1041251335110352020 |
7 | 32626000551346302 |
oct | 3164163602717254 |
9 | 486008777802443 |
10 | 113540112031404 |
11 | 331a5100291243 |
12 | 10898a0195b610 |
13 | 4b47a2c298546 |
14 | 200752946c272 |
15 | d1d68b300e89 |
hex | 67439e0b9eac |
113540112031404 has 24 divisors (see below), whose sum is σ = 264960323849200. Its totient is φ = 37841933185344.
The previous prime is 113540112031399. The next prime is 113540112031421. The reversal of 113540112031404 is 404130211045311.
It is a happy number.
It is a super-3 number, since 3×1135401120314043 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 596253979 + ... + 596444370.
Almost surely, 2113540112031404 is an apocalyptic number.
It is an amenable number.
113540112031404 is an abundant number, since it is smaller than the sum of its proper divisors (151420211817796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113540112031404 is a wasteful number, since it uses less digits than its factorization.
113540112031404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1192706289 (or 1192706287 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 113540112031404 its reverse (404130211045311), we get a palindrome (517670323076715).
The spelling of 113540112031404 in words is "one hundred thirteen trillion, five hundred forty billion, one hundred twelve million, thirty-one thousand, four hundred four".
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