Base | Representation |
---|---|
bin | 110100110111110011… |
… | …1000011111001011011 |
3 | 101212001220122221212222 |
4 | 1221233213003321123 |
5 | 3330013131112001 |
6 | 124054343454255 |
7 | 11126445121355 |
oct | 1515747037133 |
9 | 355056587788 |
10 | 113541660251 |
11 | 44175341958 |
12 | 1a008a5738b |
13 | a926191966 |
14 | 56d17080d5 |
15 | 2e47ed361b |
hex | 1a6f9c3e5b |
113541660251 has 2 divisors, whose sum is σ = 113541660252. Its totient is φ = 113541660250.
The previous prime is 113541660241. The next prime is 113541660263. The reversal of 113541660251 is 152066145311.
It is a weak prime.
It is an emirp because it is prime and its reverse (152066145311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113541660251 is a prime.
It is a super-2 number, since 2×1135416602512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113541660241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56770830125 + 56770830126.
It is an arithmetic number, because the mean of its divisors is an integer number (56770830126).
Almost surely, 2113541660251 is an apocalyptic number.
113541660251 is a deficient number, since it is larger than the sum of its proper divisors (1).
113541660251 is an equidigital number, since it uses as much as digits as its factorization.
113541660251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 35.
The spelling of 113541660251 in words is "one hundred thirteen billion, five hundred forty-one million, six hundred sixty thousand, two hundred fifty-one".
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