Base | Representation |
---|---|
bin | 1000110110011111011… |
… | …0010011110000011111 |
3 | 112112111202021120101222 |
4 | 2031213312103300133 |
5 | 4442412413122221 |
6 | 153505213123555 |
7 | 13662224623343 |
oct | 2154766236037 |
9 | 475452246358 |
10 | 152066145311 |
11 | 59544413763 |
12 | 2557a7895bb |
13 | 11455645952 |
14 | 7507d47623 |
15 | 3e501aa9ab |
hex | 2367d93c1f |
152066145311 has 2 divisors, whose sum is σ = 152066145312. Its totient is φ = 152066145310.
The previous prime is 152066145277. The next prime is 152066145349. The reversal of 152066145311 is 113541660251.
It is a weak prime.
It is an emirp because it is prime and its reverse (113541660251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152066145311 - 222 = 152061951007 is a prime.
It is a super-2 number, since 2×1520661453112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152066145611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76033072655 + 76033072656.
It is an arithmetic number, because the mean of its divisors is an integer number (76033072656).
Almost surely, 2152066145311 is an apocalyptic number.
152066145311 is a deficient number, since it is larger than the sum of its proper divisors (1).
152066145311 is an equidigital number, since it uses as much as digits as its factorization.
152066145311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 35.
The spelling of 152066145311 in words is "one hundred fifty-two billion, sixty-six million, one hundred forty-five thousand, three hundred eleven".
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