113542113031031 has 2 divisors, whose sum is σ = 113542113031032. Its totient is φ = 113542113031030.

The previous prime is 113542113031013. The next prime is 113542113031033. The reversal of 113542113031031 is 130130311245311.

Together with previous prime (113542113031013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113542113031031 is a prime.

It is a super-2 number, since 2×113542113031031² (a number of 29 digits) contains 22 as substring.

Together with 113542113031033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113542113030985 and 113542113031003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113542113031033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56771056515515 + 56771056515516.

It is an arithmetic number, because the mean of its divisors is an integer number (56771056515516).

Almost surely, 2^{113542113031031} is an apocalyptic number.

113542113031031 is a deficient number, since it is larger than the sum of its proper divisors (1).

113542113031031 is an equidigital number, since it uses as much as digits as its factorization.

113542113031031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 29.

Adding to 113542113031031 its reverse (130130311245311), we get a palindrome (243672424276342).

The spelling of 113542113031031 in words is "one hundred thirteen trillion, five hundred forty-two billion, one hundred thirteen million, thirty-one thousand, thirty-one".