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113543212304503 is a prime number
BaseRepresentation
bin11001110100010001010110…
…110101100000100001110111
3112220000121212200121021200001
4121310101112311200201313
5104340242444322221003
61041253010500132131
732626140435262342
oct3164212665404167
9486017780537601
10113543212304503
11331a645130a313
1210899528097047
134b4810468a977
1420077410d7459
15d1d7bd5a061d
hex674456d60877

113543212304503 has 2 divisors, whose sum is σ = 113543212304504. Its totient is φ = 113543212304502.

The previous prime is 113543212304453. The next prime is 113543212304549. The reversal of 113543212304503 is 305403212345311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113543212304503 - 241 = 111344189048951 is a prime.

It is a super-2 number, since 2×1135432123045032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113543219304503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56771606152251 + 56771606152252.

It is an arithmetic number, because the mean of its divisors is an integer number (56771606152252).

Almost surely, 2113543212304503 is an apocalyptic number.

113543212304503 is a deficient number, since it is larger than the sum of its proper divisors (1).

113543212304503 is an equidigital number, since it uses as much as digits as its factorization.

113543212304503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 113543212304503 its reverse (305403212345311), we get a palindrome (418946424649814).

The spelling of 113543212304503 in words is "one hundred thirteen trillion, five hundred forty-three billion, two hundred twelve million, three hundred four thousand, five hundred three".