Base | Representation |
---|---|
bin | 1010010100111100110101… |
… | …0100001111101111111001 |
3 | 1111012112100111001222111022 |
4 | 2211033031110033233321 |
5 | 2442020112024344433 |
6 | 40052233531312225 |
7 | 2251242361452503 |
oct | 245171524175771 |
9 | 44175314058438 |
10 | 11355043199993 |
11 | 3688712952039 |
12 | 1334824bab675 |
13 | 644a11a9848c |
14 | 2b3830b12d73 |
15 | 14a586349698 |
hex | a53cd50fbf9 |
11355043199993 has 2 divisors, whose sum is σ = 11355043199994. Its totient is φ = 11355043199992.
The previous prime is 11355043199987. The next prime is 11355043200001. The reversal of 11355043199993 is 39999134055311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9307362335209 + 2047680864784 = 3050797^2 + 1430972^2 .
It is an emirp because it is prime and its reverse (39999134055311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11355043199993 - 222 = 11355039005689 is a prime.
It is not a weakly prime, because it can be changed into another prime (11355043199893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677521599996 + 5677521599997.
It is an arithmetic number, because the mean of its divisors is an integer number (5677521599997).
Almost surely, 211355043199993 is an apocalyptic number.
It is an amenable number.
11355043199993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11355043199993 is an equidigital number, since it uses as much as digits as its factorization.
11355043199993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17714700, while the sum is 62.
The spelling of 11355043199993 in words is "eleven trillion, three hundred fifty-five billion, forty-three million, one hundred ninety-nine thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •