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11355043199993 is a prime number
BaseRepresentation
bin1010010100111100110101…
…0100001111101111111001
31111012112100111001222111022
42211033031110033233321
52442020112024344433
640052233531312225
72251242361452503
oct245171524175771
944175314058438
1011355043199993
113688712952039
121334824bab675
13644a11a9848c
142b3830b12d73
1514a586349698
hexa53cd50fbf9

11355043199993 has 2 divisors, whose sum is σ = 11355043199994. Its totient is φ = 11355043199992.

The previous prime is 11355043199987. The next prime is 11355043200001. The reversal of 11355043199993 is 39999134055311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9307362335209 + 2047680864784 = 3050797^2 + 1430972^2 .

It is an emirp because it is prime and its reverse (39999134055311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11355043199993 - 222 = 11355039005689 is a prime.

It is not a weakly prime, because it can be changed into another prime (11355043199893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677521599996 + 5677521599997.

It is an arithmetic number, because the mean of its divisors is an integer number (5677521599997).

Almost surely, 211355043199993 is an apocalyptic number.

It is an amenable number.

11355043199993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11355043199993 is an equidigital number, since it uses as much as digits as its factorization.

11355043199993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17714700, while the sum is 62.

The spelling of 11355043199993 in words is "eleven trillion, three hundred fifty-five billion, forty-three million, one hundred ninety-nine thousand, nine hundred ninety-three".