Base | Representation |
---|---|
bin | 10010001100001000001100… |
… | …01011010011101110001111 |
3 | 12020121212202102111110111222 |
4 | 21012010012023103232033 |
5 | 20220321211304232221 |
6 | 221023203140033555 |
7 | 11265561554453444 |
oct | 1106040613235617 |
9 | 166555672443458 |
10 | 39999134055311 |
11 | 118215a0443002 |
12 | 45a01250928bb |
13 | 1941b96065b62 |
14 | 9c3d7b4a59cb |
15 | 495708bba9ab |
hex | 2461062d3b8f |
39999134055311 has 2 divisors, whose sum is σ = 39999134055312. Its totient is φ = 39999134055310.
The previous prime is 39999134055271. The next prime is 39999134055317. The reversal of 39999134055311 is 11355043199993.
It is a strong prime.
It is an emirp because it is prime and its reverse (11355043199993) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-39999134055311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (39999134055317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19999567027655 + 19999567027656.
It is an arithmetic number, because the mean of its divisors is an integer number (19999567027656).
Almost surely, 239999134055311 is an apocalyptic number.
39999134055311 is a deficient number, since it is larger than the sum of its proper divisors (1).
39999134055311 is an equidigital number, since it uses as much as digits as its factorization.
39999134055311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17714700, while the sum is 62.
The spelling of 39999134055311 in words is "thirty-nine trillion, nine hundred ninety-nine billion, one hundred thirty-four million, fifty-five thousand, three hundred eleven".
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