Base | Representation |
---|---|
bin | 1010010100111100110101… |
… | …0100001111110000000001 |
3 | 1111012112100111001222111121 |
4 | 2211033031110033300001 |
5 | 2442020112024400001 |
6 | 40052233531312241 |
7 | 2251242361452514 |
oct | 245171524176001 |
9 | 44175314058447 |
10 | 11355043200001 |
11 | 3688712952046 |
12 | 1334824bab681 |
13 | 644a11a98497 |
14 | 2b3830b12d7b |
15 | 14a5863496a1 |
hex | a53cd50fc01 |
11355043200001 has 2 divisors, whose sum is σ = 11355043200002. Its totient is φ = 11355043200000.
The previous prime is 11355043199993. The next prime is 11355043200181. The reversal of 11355043200001 is 10000234055311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9922808702401 + 1432234497600 = 3150049^2 + 1196760^2 .
It is a cyclic number.
It is not a de Polignac number, because 11355043200001 - 23 = 11355043199993 is a prime.
It is not a weakly prime, because it can be changed into another prime (11355043200701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677521600000 + 5677521600001.
It is an arithmetic number, because the mean of its divisors is an integer number (5677521600001).
Almost surely, 211355043200001 is an apocalyptic number.
It is an amenable number.
11355043200001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11355043200001 is an equidigital number, since it uses as much as digits as its factorization.
11355043200001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 11355043200001 its reverse (10000234055311), we get a palindrome (21355277255312).
The spelling of 11355043200001 in words is "eleven trillion, three hundred fifty-five billion, forty-three million, two hundred thousand, one".
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